Use 1/2mv2max=hv??? and W=hVo
57) If maximum velocity with which an electron can be emitted from a photo cell is 3.75?108cms?1, then stopping potential is
Answer is:
40 volts
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
1.64 eV
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3 V
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
Answer is:
2.6??10?19?J
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
6.54x10-34J-secs
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)