use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
59) If the frequency of incident light on a certain metal is 8.2??1014Hz having threshold frequency of 3.3??1014?Hz , then cut off potential is
Answer is:
3 V
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
2.6??10?19?J
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
6.54x10-34J-secs
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
Answer is:
1.7??107ms?1
Explanation:
Use BeV=eE
Answer is:
the velocity of electron decreases
Explanation:
Use BeV=eE