use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
61) Threshold wavelength for metal is 10,000 Å. If light of wavelength 5461Å is incident on it then stopping potential is 1.02 V, then value of Planck's constant is
Answer is:
6.54x10-34J-secs
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
1.7??107ms?1
Explanation:
Use BeV=eE
Answer is:
the velocity of electron decreases
Explanation:
Use BeV=eE
Answer is:
Parallel and separate
Explanation:
In Thomson?s method for finding specific charge of positive rays, the electric and magnetic fields are Parallel and separate
Answer is:
their masses are very large
Explanation:
The specific charge for positive rays is much less than that for cathode rays. This is because their masses are very large