use W=hVo and E = hc/(/lambda)
60) If light of frequency?1015?Hz is incident on sodium having work function 2.5eV,then energy of emitted photoelectrons is
Answer is:
2.6??10?19?J
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
6.54x10-34J-secs
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
Answer is:
1.7??107ms?1
Explanation:
Use BeV=eE
Answer is:
the velocity of electron decreases
Explanation:
Use BeV=eE
Answer is:
Parallel and separate
Explanation:
In Thomson?s method for finding specific charge of positive rays, the electric and magnetic fields are Parallel and separate