use W=hVo and E = hc/(/lambda)
56) If threshold wavelength for tungsten is 2300?A0, then energy of the electrons emitted by UV light of wavelength 1800?A0?is
Answer is:
2.4??10?12?erg
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
40 volts
Explanation:
Use 1/2mv2max=hv??? and W=hVo
Answer is:
1.64 eV
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3 V
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)
Answer is:
2.6??10?19?J
Explanation:
use W=hVo and E = hc/(/lambda)