Use 1/2mv2max=hv???
55) When ultraviolet light of wavelength 1000?A0?is incident on molybdenum, then the maximum velocity of ejected electron (given: work function of molybdenum = 5.0eV) is
Answer is:
1.6??108cms?1
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
2.4??10?12?erg
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
40 volts
Explanation:
Use 1/2mv2max=hv??? and W=hVo
Answer is:
1.64 eV
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3 V
Explanation:
use W=hVo and E = hc/(/lambda) and threshold frequency=c/(/ambda)