use W=hVo and E = hc/(/lambda)
48) Wavelength associated with a photon having energy 4.14eV is
Answer is:
4000 Ao
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
4.8??1014Hz
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3.3??10?19?J
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3.6??10?7?m
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
4.3??1014Hz
Explanation:
use W=hVo and E = hc/(/lambda)