use W=hVo and E = hc/(/lambda)
49) If the work function of a material is 2eV, then minimum frequency of light required to emit photo-electrons is
Answer is:
4.8??1014Hz
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
3.3??10?19?J
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
3.6??10?7?m
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
4.3??1014Hz
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
12.4 eV
Explanation:
use W=hVo and E = hc/(/lambda)