use W=hVo and E = hc/(/lambda)
51) If work function of a metal surface is 3.45 eV ,then maximum wavelength of a photon required to eject a photoelectron is
Answer is:
3.6??10?7?m
Explanation:
Related Dual Nature of Radiation MCQ with Answers
Answer is:
4.3??1014Hz
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
12.4 eV
Explanation:
use W=hVo and E = hc/(/lambda)
Answer is:
2??105ms?1
Explanation:
Use 1/2mv2max=hv???
Answer is:
1.6??108cms?1
Explanation:
Use 1/2mv2max=hv???