30 min
As the amount of radioactive isotope remaining after 2 hrs is 1/16 of the intial amount,the eauation N=(N)initial x (exp(-kt)), here k denote lambda, takes the form N)initial/16=N)initial x (exp(-kt)) i.e., exp(-kt)=1/16 => -kt= log(1/16) .....[taking log on both the sides] =>-kt=-4log2 now time taken is 2 hrs therfore, 2k=4log2 => k=2log2 now half life =log2/k=1/2hrs=30 mins ,hence the answer (ii) THIS WAS FOR NCERT TRADITIONAL WORMS NEXT SOLUTION IS A BETTER APPROACH the amount left after n-half lives=initial amount/(2 raised to power n),now as the final amount 1/16 ,i.e., 1/(2 raised to power 4) of the initial amount, 4 half lives have passed therefore, 4(half life)=2 hrs => half life=30 min
7/8 part of the mass of the substance disintegrates in 30 days
The half life of a radioactive substance is 10 days. This means that 7/8 part of the mass of the substance disintegrates in 30 days
the strength of the nuclear force between the nucleons of its atoms
The half-life of a radioactive substance depends upon the strength of the nuclear force between the nucleons of its atoms
1:1
the rate of disintegration is proportional to number of radioactive atoms present initially in source
91234
Beta-minus emission changes a neutron into a proton, so the atomic number rises by one. The mass doesn't change