Atoms and Nuclei MCQ with Answers

46) A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in ?head-on? to a particular lead nucleus and stops 6.5??10^?14?m away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of the alpha particle is 6.64??10^?27?kg . Calculate the electrostatic potential energy at the instant that the alpha particle stops. Express your result in MeV.

Answer is:

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

Answer is:

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

Answer is:

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

Answer is:

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

Answer is:

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E