If HCOOH + NaOH ⇶ HCOONa + H<sub>2</sub>O, ΔH = −13.1 kcal, then enthalpy of dissociation of HCOOH will be:

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180

Physical Chemistry MCQ with Answers

180) If HCOOH + NaOH ⇶ HCOONa + H₂O, ΔH = −13.1 kcal, then enthalpy of dissociation of HCOOH will be:

600 cal

60 cal

−600 cal

Can not be calculated

Answer is:

600 cal

Physical Chemistry MCQ with Answers

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181) For which of the following cases, dS = dH⁄T:

A process for which ΔC_p = 0, but ΔC_v ≠ 0

An isothermal process in which reversible phase transition takes place

An isobaric process

An adiabatic process

Answer is:

An adiabatic process

182) The latent heat of vapourisation of a liquid at 500 K and 1 atm pressure is 10 kcal⁄mol. What will be the change in internal energy of 3 mol of liquid at same termperature?

13 kcal

−13 kcal

27 kcal

−27 kcal

Answer is:

27 kcal

Explanation:

ΔH = ΔE + ΔnRT

183) When a diatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TVⁿ = constant. What will be the value of n?

0.6

0.4

0.2

Answer is:

0.4

Explanation:

TV^γ−1 = constant. For diatomic gas, γ = 7⁄5

184) The bond enthalpies of H₂, X₂ and HX are in the ratio of 2:1:2. Enthaply of formation of HX is −50KJ⁄mol. The bond enthalpy of X₂ is:

100 KJ⁄mol

200 KJ⁄mol

300 KJ⁄mol

400 KJ⁄mol

Answer is:

100 KJ⁄mol

Physical Chemistry MCQ with Answers

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180) If HCOOH + NaOH ⇶ HCOONa + H2O, ΔH = −13.1 kcal, then enthalpy of dissociation of HCOOH will be:

600 cal

Physical Chemistry MCQ with Answers

Related Physical Chemistry MCQ with Answers

181) For which of the following cases, dS = dH⁄T:

An adiabatic process

182) The latent heat of vapourisation of a liquid at 500 K and 1 atm pressure is 10 kcal⁄mol. What will be the change in internal energy of 3 mol of liquid at same termperature?

27 kcal

183) When a diatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TVn = constant. What will be the value of n?

0.4

184) The bond enthalpies of H2, X2 and HX are in the ratio of 2:1:2. Enthaply of formation of HX is −50KJ⁄mol. The bond enthalpy of X2 is:

100 KJ⁄mol

Physical Chemistry MCQ with Answers

180) If HCOOH + NaOH ⇶ HCOONa + H₂O, ΔH = −13.1 kcal, then enthalpy of dissociation of HCOOH will be:

183) When a diatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TVⁿ = constant. What will be the value of n?

184) The bond enthalpies of H₂, X₂ and HX are in the ratio of 2:1:2. Enthaply of formation of HX is −50KJ⁄mol. The bond enthalpy of X₂ is: