ΔH = ΔE + ΔnRT
182) The latent heat of vapourisation of a liquid at 500 K and 1 atm pressure is 10 kcal⁄mol. What will be the change in internal energy of 3 mol of liquid at same termperature?
Answer is:
27 kcal
Explanation:
Related Physical Chemistry MCQ with Answers
Answer is:
0.4
Explanation:
TVγ−1 = constant. For diatomic gas, γ = 7⁄5
Answer is:
100 KJ⁄mol
Answer is:
−2.49 kJ
Answer is: