50) A centrifugal pump running at 500 rpm and at its maximum efficiency is delivering a head of 30 m at a flow rate of 60 litres/min. If the rpm is changed to 1000, then the head H in meters and flow rate Q in liters/min at maximum efficiency are estimated to

H = 60, Q=120

H = 120, Q= 120

H = 60, Q = 480

H = 120, Q = 30

Answer is:

H = 120, Q= 120

0.3 + 0.02D

0.5 + 0.12D

0.3 + 0.008D

0.8 + 0.02D

Answer is:

(MRR)/(TWR)

(TWR)/(MRR)

(MRR-TWR)/(MRR)

(TWR-MRR)/(TWR)

Answer is:

Answer is:

remove burr and improve accuracy

remove excess metal

remove scrap

all of the above

Answer is: