34) A lamp and a screen are set up 100 cm apart and a convex lens is placed between them. The two positions of the lens forming real images on the screen are 40 cm apart. What is the focal length of the lens ?
21 cm
Related Optics MCQ with Answers
1.55
n1/u +n2/v=(n2-n1)/r for first refraction by convex surface: u??, v=rn2/(n2-n1) for plane reflection: r is infinite,v'=-v for second refraction: 1.5/v' -1/v''=(1-1.5)/r 1/v''+1/v=1/f power=1/f
11 cm
The curved silvered surface will behave as a concave lens of focal length fm=R/2=?22/2 =?11cm =?0.11m And hence PM=the power of mirror =?1/fM=?1/?0.11=1/0.11D Further as focal length of lens is 20 cm ie 0.2m its power is P2=1/f2P2 =1/20D Now as in image formation, light after passing through the lens will be reflected back by curved mirror through lens again . P=PL+PM+PL =2PL+PM P=2/0.2+1/0.11=210/11D So, focal length of equivalent mirror. F=?1/P=11/210m ?110/21cm ie silvered lens behaves as a concave mirror of focal length (110/21)cm So far object at a distance 10 cm in front of it. 1/V+1/?10=21/110 i,e V=?11cm The image will be 11 cm in front of silvered lens and will be real. Hence c is the correct answer.