Angle of reflection = angle of incidence (B) Use Snell's law. n1/n2 = sin(theta1)/sin(theta2) But in order to use snell's law, you need to get the ratio of n's first. You can do that, though, using the fact that light incoming at the critical angle refracts at 90 degrees. n1/n2 = sin(critical angle)/sin(90 degrees)= sin (critical angle) Therefore, for your answer to part (B) sin (refracted angle) = sin (incident angle)sin(critical angle).
128) The critical angle for total internal reflection at a liquid°air interface is 42.5°°If a ray of light traveling in air has an angle of incidence at the interface of 35°°what angle does the refracted ray in the liquid make with the normal?
Answer is:
22.8°
Explanation:
Related Optics MCQ with Answers
Answer is:
0.375?I0
Explanation:
use malus law I = Iocos2/theta
Answer is:
1.4
Explanation:
use malus law I = Iocos2/theta