Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s Ht=1960m. To Find: The range of the projectile (R). Its actually a Projetile motion . For a projectile Ht=1/2*g*t*t.There fore we get t= 20s. R=V*t=166.66*20=3333.33m/s=3.333Km/hr.
89) An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
Answer is:
3.33 km
Explanation:
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