The maximum speed for the overturn of a car moving on a circular track is given by, v=underroot(co-efficient of friction X radius X acceleration due to gravity) v=underroot(0.2 X 100 X 9.8) v=14m/s.
34) Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
Answer is:
14 m/s
Explanation:
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