(1/(λ1)= (1)2((1/(22))-(1/(32)))
=>(1/(λ2)= (2)2((1/(22))-(1/(42)))
=>(λ2)/(λ1)=(5*4*16)/(4*4*9*12)= 5/27
=>(λ2) = (6561*5)/27 = 1215A o
1) The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Ao,The wavelength of the second spectral line in the Balmer series of singly-ionized helium atom is
Answer is:
1215Ao
Explanation:
Related General Physics MCQ with Answers
Answer is:
8.50 kHz
Explanation:
frequency reflected by wall f’
f’ = 8 *103[ 320/(320 - 10)]
frequency heared by car driver f″= [(320 + 10)/320]f’
f″ = 8* 103 (32/31) *(33/32) =8.50 kHz
Answer is:
They will come out travelling along parallel paths
Explanation:
r = mv/qB
They go in different direction but come out along parallel paths.
T = 2(π) m/qB
as m is different, so T is also different
Answer is:
((σA)/(σB)) = ((RA)/(RB))
Explanation:
1) EA = 0
2)(QA/RA) = (QB/RQB)
=>RA > RB
=>QA > QB
3)σ R = V
4) E = σ/(2 Eo
Answer is:
((Ne2)/(mEo))1/2
Explanation:
ω = θ/T = T-1
=>D.f. of ((Ne2)/(mEo))1/2 = (((1/L3)*(I2T2)*(ML3T-2))/(M*(I2T2)))
=> D.f = T-1