44) In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of???-particles by a thin foil?

Answer is:

Thomson's model

Explanation:

In Thomson model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of???-particles by a thin foil

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45) An alpha particle (charge 2e) is aimed directly at a gold nucleus (charge 79e). What minimum initial kinetic energy must the alpha particle have to approach within 5.0 * 10-14 m of the center of the gold nucleus before reversing direction? Assume that the gold nucleus, which has about 50 times the mass of an alpha particle, remains at rest.

Answer is:

4.6 MeV

Explanation:

use N(/theta)d/theta = 2I(/theta)e^{((/theta)*(/theta))/((/theta)*(/theta)))}d((/theta)))/((/theta)*(/theta))

46) A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in ?head-on? to a particular lead nucleus and stops 6.5??10^?14?m away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of the alpha particle is 6.64??10^?27?kg . Calculate the electrostatic potential energy at the instant that the alpha particle stops. Express your result in MeV.

Answer is:

3.63 MeV

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

47) A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in ?head-on? to a particular lead nucleus and stops 6.5??10^?14?m away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of the alpha particle is 6.64??10^?27?kg What initial kinetic energy (in MeV) did the alpha particle have?

Answer is:

3.63 MeV

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

48) A triply ionized beryllium ion?Be³⁺, (a beryllium atom with three electrons removed), behaves very much like a hydrogen atom except that the nuclear charge is four times as great. (a) What is the ground-level energy of?Be³⁺?? How does this compare to the ground level energy of the hydrogen atom?

Answer is:

-218 eV, 16 times

Explanation:

kinetic energy is the negative of total energy. K.E. = -E also P.E. is equal to negative of two time of total energy. P.E.=-2E

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44) In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of???-particles by a thin foil?

Thomson's model

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Related Atoms and Nuclei MCQ with Answers

4.6 MeV

3.63 MeV

3.63 MeV

-218 eV, 16 times

Atoms and Nuclei MCQ with Answers