For fcc lattice, 4r = √2a.
70) Xenon crystallizes in fcc lattice and the edge of the unit cell is 620 pm, then the radius of Xe atom is:
Answer is:
219.20 pm
Explanation:
Related Physical Chemistry MCQ with Answers
Answer is:
693 pm
Explanation:
In bcc, body diagonal = √3a.
Answer is:
fcc
Explanation:
ρ = (Z x M)⁄(N x a3)