269) The rate law for a reaction between the substances A and B is given by rate = K[A]n[B]m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:
Answer is:
2n−m
Related Physical Chemistry MCQ with Answers
Answer is:
1.776
Answer is:
(1000⁄2.303) K
Answer is: