pOH = pKb + log ([B−]⁄[HB])
264) In a buffer solution containing equal concentration of B− and HB, the Kb for B− is 10−10. The pH of buffer solution is:
Answer is:
4
Explanation:
Related Physical Chemistry MCQ with Answers
Answer is:
11.74
Answer is:
0.0005M
Explanation:
Concentration of Ba(OH)2 = 10−pOH⁄2
Answer is: