pOH = pKb + log ([salt]⁄[base])
246) 0.15 mol of pyridinium chloride has added to 500 cc of 0.2M pyridine solution (Kb for pyridine is 1.5 x 10−9M). pH is:
Answer is:
5
Explanation:
Related Physical Chemistry MCQ with Answers
Answer is:
Decrease
Explanation:
pOH = pKb + log ([salt]⁄[base])
Answer is:
6.5
Explanation:
pH = 7 + 0.5pKa − 0.5pKb
Answer is:
1.51 x 10−9
Explanation:
pH = −0.5 [log Kw − log Kb + log C]