pH = (1⁄2) x (pKw + pKa + pKb)
219) 100 mL HCN of 0.1M is titrated with 100 mL 0.1M NaOH solution. At the neutral point, pH of this solution will be: (pKa of HCN = 4.74)
Answer is:
8.72
Explanation:
Related Physical Chemistry MCQ with Answers
Answer is:
11.25
Explanation:
[H+] = 10−pH
Answer is:
3.39 x 10−11
Answer is:
0.1
Explanation:
Buffer capacity = [H+] ⁄ change in pH
Answer is:
−1.142 kJ
Explanation:
Limiting reagent = HCl