200) At 1000 K, the Kp for the reaction of CO2 (g) with excess of graphite to form CO (g) is 9 atm. Then the mole % of CO in the equilibrium mixture of gases is:
Answer is:
0.75
Related Physical Chemistry MCQ with Answers
Answer is:
Both Kf and Kb change by same fraction
Explanation:
On addition of catalyst, Keq does not change.
Answer is:
0.5
Explanation:
Kc = Kf⁄Kb
Answer is:
1.5 mol⁄L
Explanation:
Molar concentration = Number of moles ⁄ Vol(L)