19) To neutralize 20 mL NaOH, the volume if 1M HNO3 is:
Answer is:
4 mL
Related Physical Chemistry MCQ with Answers
Answer is:
0.15
Explanation:
Weight percentage of NaCl = (weight of NaCl⁄weight of solution) x 100
Answer is:
0.077
Explanation:
Volume percentage of ethanol = (volume of ethanol⁄volume of solution) x 100
Answer is:
0.075
Explanation:
7.5% of KCl (w⁄V) : 7.5 gm KCl present in 100 mL of solution
Answer is:
0.1N
Explanation:
Normality = (w⁄GEM) x (1000⁄V(mL))