165) 4 gm of argon in a bulb at a temperature of T K, had a pressure P atm. When the bulb was placed in hotter bath at a temperature 50o more than the first one, 0.8 gm of gas had to be removed to get the original pressure. T is equal to:
Answer is:
200 K
Related Physical Chemistry MCQ with Answers
Answer is:
3.82 x 10−4 mol
Explanation:
n = PV⁄RT
Answer is:
1.428
Answer is:
15 kg
Explanation:
P1⁄P2 = w1⁄w2
Answer is:
Atmospheric pressure minus aqueous tension at that temperature
Explanation:
P (dry O2) + P (water vapour) = P (wet O2)