IP of X is a smaller value, therefore an alkali metal. IP of Q is comparatively higher, hence halogen. So, QOH is a hypohalous acid (pH < 7).
26) Solutions of equal strength of XOH nad QOH are prepared. The ionisation potential of X and Q are 5.1 and 13.0 eV respectively, whereas their electronegativities are 0.9 and 3.2. Spot the incorrect conclusion:
Answer is:
The pH of QOH solution will be more than 7
Explanation:
Related Inorganic Chemistry MCQ with Answers
Answer is:
Si
Explanation:
The jump in IP values exist in IP5 and thus removal of fifth electron occurs from inner shell. So, element contains 4 electrons in its valence shell.
Answer is:
Ionic
Explanation:
If C is an alkali, A should be a halogen non metal.
Answer is:
2 EN − IP − EA = 0
Explanation:
EN = (IP + EA) ⁄ 2