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Objective Questions
GS
GS Set-1
Chemistry
Inorganic Chemistry
252

Inorganic Chemistry MCQ with Answers

252) Reagent used in the qualitative analysis of group IV is:

HCl

H₂S (alkaline)

(NH_4>/sub>)₂S

None of these

Answer is:

H₂S (alkaline)

Explanation:

In presence of NH₄OH, dissociation of H₂S is remarkably high, so increases the solubility product of group IV sulphides.

Inorganic Chemistry MCQ with Answers

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253) Distinguishing reagent between silver and lead salts is:

H₂S gas

Hot dilute HCl solution

NH₄Cl (solid) + NH₄OH solution

NH₄Cl (solid) + (NH₄)₂CO₃ solution

Answer is:

Hot dilute HCl solution

Explanation:

Both Pb and Ag form white ppt. of their chlorides. But PbCl₂ is soluble in hot water while AgCl is not.

254) The ion that can not precipitated by both HCl and H₂S is:

Pb²⁺

Cu⁺

Ag⁺

Sn²⁺

Answer is:

Cu⁺

255) When H₂S is passed through Hg₂S, we get:

HgS

HgS + Hg₂S

Hg₂S + Hg

Hg₂S

Answer is:

Hg₂S + Hg

256) How do we differentiate between Fe³⁺ and Cr³⁺ in group III?

(a) By taking excess of NH₄OH solution

(b) By increasing NH₄⁺ ion concentration

Both (b) and (c)

Answer is:

Both (b) and (c)

Inorganic Chemistry MCQ with Answers

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252) Reagent used in the qualitative analysis of group IV is:

H2S (alkaline)

Inorganic Chemistry MCQ with Answers

Related Inorganic Chemistry MCQ with Answers

253) Distinguishing reagent between silver and lead salts is:

Hot dilute HCl solution

254) The ion that can not precipitated by both HCl and H2S is:

Cu+

255) When H2S is passed through Hg2S, we get:

Hg2S + Hg

256) How do we differentiate between Fe3+ and Cr3+ in group III?

Both (b) and (c)

Inorganic Chemistry MCQ with Answers

H₂S (alkaline)

254) The ion that can not precipitated by both HCl and H₂S is:

Cu⁺

255) When H₂S is passed through Hg₂S, we get:

Hg₂S + Hg

256) How do we differentiate between Fe³⁺ and Cr³⁺ in group III?