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Engineering
Mechanical
ME Set-1
Machine Design
405

Machine Design MCQ with Answers

405) The product of the diametral pitch and circular pitch is equal to

1/Pi

Pi x number of teeth

Answer is:

Pi

Machine Design MCQ with Answers

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406) If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively, and T_c is the centrifugal tension, then initial tension in the belt is equal to

T₁ - T₂ + T_c

T₁ + T₂ + T_c

(T₁ - T₂ + T_c)/2

(T₁ + T₂ + T_c)/2

Answer is:

(T₁ + T₂ + T_c)/2

407) The smallest diameter of an external or internal screw thread is known as

minor diameter

major diameter

pitch diameter

none of these

Answer is:

minor diameter

408) The process which improves the machinability of steels, but lowers the hardness and tensile strength is

normalising

full annealing

process annealing

spheroidising

Answer is:

spheroidising

409) Which of the following statement is wrong ?

A key is used as a temporary fastening

A key is subjected to tensile stresses

A key is always inserted parallel to the axis of the shaft

A key prevents relative motion between the shaft and boss of the pulley

Answer is:

A key is subjected to tensile stresses

Which of the following statement is wrong ?

Machine Design MCQ with Answers

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405) The product of the diametral pitch and circular pitch is equal to

Pi

Machine Design MCQ with Answers

Related Machine Design MCQ with Answers

406) If T1 and T2 are the tensions on the tight and slack sides of the belt respectively, and Tc is the centrifugal tension, then initial tension in the belt is equal to

(T1 + T2 + Tc)/2

407) The smallest diameter of an external or internal screw thread is known as

minor diameter

408) The process which improves the machinability of steels, but lowers the hardness and tensile strength is

spheroidising

409) Which of the following statement is wrong ?

A key is subjected to tensile stresses

Machine Design MCQ with Answers

406) If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively, and T_c is the centrifugal tension, then initial tension in the belt is equal to

(T₁ + T₂ + T_c)/2