215) Consider the program
main( )
{
int y = 1;
printf ("%d", (*(char *)&x)) :
}
If the machine in which this program is executed is little-endian (meaning, the lower signifi-cant digits occupy lower addresses), then the output will he

216) The program
main()
{
int i = 5;
i = (++i) / (i++);
printf ("%d", i);
prints

217) The output of the following program
main( )
{
int a = 1, b = 2, c = 3;
printf("%d", a += (a += 3, 5, a));
}
will be

218) The statement printf ("%d", 10 ? 0 ? 5 : 11 : 12 ) ;

219) The statement printf ("%d", ++5) ; prints